The problem seeks the dimension of the cylindrical tin can that is capable of holding 14 cubic inches of liquid, and has the smallest surface area. Before we can determine the dimension, let us consider the volume, V, of this cylindrical tin can, which is the product of the area of the circular base with radius r, and the height h of the cylinder, and the surface area of the tin can, A, which is the area of the circular base, the circular top, and around the sides. V= πr2h (1) 14= πr2h h= 14πr2 (2) A=2πr2+ ...
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The Last Stand of the Tin Can Sailors: The Extraordinary World War II Story of the U.S Navy’s Finest Hour serves as a chronicle of the Battle of Samar. The author, James Hornsfischer referred to this battle as the ultimate upset in the naval warfare history. The author brilliantly combined the different accounts from official reports and firsthand witnesses of the warfare that occurred in the Gulf of Leyte. Despite being the underdog during the encounter, the ‘tin cans’ of the American forces were able to overcome the overwhelming forces of the Japanese military. It was on January ...
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