Essays on Bode

International Operations and Management

International Operations and Management Hedley (2016) revealed that managing international operations is an increasing concern for global companies (Harrison, 2011, p.3). Some of the reasons given by upper management are to remain competitive, as a growth opportunity, and to improve profits (Harrison, 2011, p.3). Global companies revealed that the main difficulty is choosing what entry strategy to use, which includes licensing, exporting, joint venture or direct investment (Foley, 1999, p.31). The report will examine the opportunities and continuing challenges of an international operation for a global automotive company under the entry strategies of joint venture and direct investment.

International Operation Challenges and Opportunities

Joint ...

Philosophy 223

Exam is open book, open notes, however, there should be no internet use or looking at other sources (besides the Kyabgon Traleg book The Essence of Buddhism and The Monk and the Philosopher) and no talking to anyone about the exam, etc.

Remember, “Karma means nobody gets away with nothing.” Ruth Denison

Please observe the academic honesty policies of the College. I am obliged to report any suspicion of violation. See the Dean’s office or me if you have any questions. Especially in a take-home exam situation, it is important to avoid even the appearance of impropriety. Also, give credit to other sources, even if just to say, ...

Philosophy 223

Exam is open book, open notes, however, there should be no internet use or looking at other sources (besides the Kyabgon Traleg book The Essence of Buddhism and The Monk and the Philosopher) and no talking to anyone about the exam, etc.

Remember, “Karma means nobody gets away with nothing.” Ruth Denison

Please observe the academic honesty policies of the College. I am obliged to report any suspicion of violation. See the Dean’s office or me if you have any questions. Especially in a take-home exam situation, it is important to avoid even the appearance of impropriety. Also, give credit to other sources, even if just to say, ...

1. The bode plot of the system is:

The zeros are located at:

f=0, 500 Hz

The poles are located at:

f=3.4, 50, 2120 Hz 2. Converting Hz to rad/s,

Zeros:

ωz1=0, ωz2=2π500=1000π

Poles:

ωp1=2π3.4=21.36, ωp2=2π50=100π, ωp3=2π2120=4240π 3. The form of the transfer function is: Hs=Kss+1000π(s+21.36)(s+100π)(s+4240π) Hs=j2.136=1=Kj2.136j2.136+1000π(j2.136+21.36)(j2.136+100π)(j2.136+4240π) 1K=7.47×10-5→K=13387

The transfer function becomes:

Hs=13387ss+1000πs+21.36s+100πs+4240π =13387ss1000π+11000πs21.36+1s100π+1s4240π+121.36100π4240π H(s)=0.4705ss1000π+1s21.36+1s100π+1s4240π+1 4. The frequency response of the transfer function is generated in MATLAB using the following code: clc s = tf('s'); wz = [1000* ...

PURPOSE

Design an active second order Low-pass filter and characterize its frequency response.EQUIPMENT AND COMPONENTS Oscilloscope Power Supply Function Generator UA741 or LM741 OP AMP 4.7 nF Capacitors

Resistors

PRELAB 1. The RC circuit is shown in the following figure. Node Voltage Analysis is done in order to generate a transfer function Tvs=V2sV1s. In the circuit, voltage at node A is also the input voltage (V1=VA), and voltage at node D is also the output voltage (V2=VD).

KCL at node B:

V1-VBR1=VB-V21/sC1+VB-VCR2 (1)

KCL at node C:

VB-VCR2=VC1/sC2 (2) V2=uVC→VC=V2u (3)

Simplifying (2):

VB=VC1+sR2C2 (4)

Then, substituting (3) to (4):

VB=V2u1+sR2C2 (5)

Substituting (3) and (5) to (1):

V1-V2u1+sR2C2R1=V2u1+sR2C2-V21sC1+V2u1+sR2C2-V2uR2 V1-V2u1+sR2C2R1=V2u1-u+sR2C21sC1+V2usR2C2R2 V1-V2u1+ ...

Objective:

This experiment is about the implementation and testing of low-pass, high-pass, and band-pass filters. The frequency response of each filter is analyzed using Bode plots. The properties of passive devices will be used to explain the response.

Equipment List:

EQUIPMENT Oscilloscope 2 Function Generators

COMPONENTS

1µF Capacitors 1 kΩ Resistors

Relevant Theory/Background Information:

A low-pass filter is a filter that allows frequencies below a cut-off frequency while filtering out frequencies above this cut-off frequency. For a simple series RC circuit, a low-pass filter can be created by connecting the input signal to the resistor and taking the output from the capacitor. The cut-off frequency ...

Introduction

When it comes to control systems, the inverted pendulum system is something that stands out from amongst the rest. Linear control concepts such as stabilization of unstable systems can be demonstrated using the inverted pendulum. Since the system is intrinsically non linear, many non linear concepts can also be demonstrated using the inverted pendulum. This system has basically two equilibrium states, one stable and the other unstable. In the stable equilibrium state, the pendulum points downwards and in the absence of any controlling forces, it returns to its original state. In the unstable equilibrium state, the pendulum points upwards. ...