Question 1a
Ha: The mean for all the groups are different H0: µ1 = µ2 = µ3 = µ4
Ha: µ1 ≠ µ2 ≠ µ3 ≠µ4Question 1b H02: µ1 = (µ2 +µ3 + µ4) H03: µ2 = (µ3 + µ4) H04: µ3 = µ4
Therefore:H01: (0) µ1 + (0) µ2 + (0) µ3 + (0) µ4
H02: (1) µ1 – (1/3) µ2 - (1/3) µ3 - (1/3) µ4H03: (0) µ1 + (1) µ2 - (1/2) µ3 - (1/2) µ4 H03: (0) µ1 + (0) µ2 + (1) µ3 - (1) µ4
Question 2Property 1 H01: (0) + (0) + (0) + (0) = 0 H02: (1) – (1/3) - (1/3) - (1/3) = 0 H03: (0) + (1) - (1/2) - (1/2) = 0 H04: (0) + (0) + (1) - (1) = 0
Property 2The sum of the product for the coefficients ...